x^2+4x-460=0

Solution for x^2+4x-460=0 equation:

x^2+4x-460=0

a = 1; b = 4; c = -460;
Δ = b2-4ac
Δ = 42-4·1·(-460)
Δ = 1856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1856}=\sqrt{64*29}=\sqrt{64}*\sqrt{29}=8\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{29}}{2*1}=\frac{-4-8\sqrt{29}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{29}}{2*1}=\frac{-4+8\sqrt{29}}{2}
$